X =
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
1.0000 1.2000 1.4000 1.6000 1.8000 2.0000
and Y=
1.0000 1.0000 1.0000 1.0000 1.0000 1.0000
1.2000 1.2000 1.2000 1.2000 1.2000 1.2000
1.4000 1.4000 1.4000 1.4000 1.4000 1.4000
1.6000 1.6000 1.6000 1.6000 1.6000 1.6000
1.8000 1.8000 1.8000 1.8000 1.8000 1.8000
2.0000 2.0000 2.0000 2.0000 2.0000 2.0000
and i need an n*2 matrix by pairing up corresponding elements of each of the matrices x and y. the
ex [ 1 1; 1.2 1; 1.4 1; 1.6 1; 1.8 1; 2 1; 1 1.2; 1.2 1.2;...............] and so on

 Akzeptierte Antwort

Stephan
Stephan am 6 Nov. 2018

0 Stimmen

x = [1 2; 3 4]
y = [5 6; 7 8]
z = [x(:) y(:)]

3 Kommentare

Bhavana Chinnabalannagari
Bhavana Chinnabalannagari am 6 Nov. 2018
For bigger matrices, it gives away only the diagonal elements
Stephan
Stephan am 6 Nov. 2018
Bearbeitet: Stephan am 6 Nov. 2018
No, see this example:
x = reshape(1:25,5,5)
y = reshape(26:50,5,5)
z = [x(:) y(:)]
result:
x =
1 6 11 16 21
2 7 12 17 22
3 8 13 18 23
4 9 14 19 24
5 10 15 20 25
y =
26 31 36 41 46
27 32 37 42 47
28 33 38 43 48
29 34 39 44 49
30 35 40 45 50
z =
1 26
2 27
3 28
4 29
5 30
6 31
7 32
8 33
9 34
10 35
11 36
12 37
13 38
14 39
15 40
16 41
17 42
18 43
19 44
20 45
21 46
22 47
23 48
24 49
25 50
Diagonal values would be 5 pairs - this are 25 pairs of values. I think this is what you expected - isnt it?
Bhavana Chinnabalannagari
Bhavana Chinnabalannagari am 6 Nov. 2018
yeah , your right.

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