how can i create figures in a for loop

I have to create a figure every 80 measurements of a row vector with length 31999 (Bn in the code). I tried to write this code but i receive only one figure with all the measurements (31999):

k= length(Bn);

for i= 1:80:(k-1)
    Bn1(i) = L(i);
    plot(Bn1);
end

any suggestion?

Answer 1

[Star Strider]

Try this:

repts = fix(numel(Bn)/80);
for k1 = 1:repts
    figure(k1)
    idxrng = (1:80) + 80*(k1-1);
    plot(Bn(idxrng), L(idxrng))
    grid
end

[Elisa Mammoliti]

thank you Star Rider, it works and it gives what i need. Also really thank you to mahdan ravi for the support!!!

[Star Strider]

My pleasure.

If my Answer helped you solve your problem, please Accept it!

[Star Strider]

Something like this could work, creating a cell array of the findchangepts outputs:

repts = fix(numel(Bn)/80);
for k1 = 1:repts
    figure(k1)
    idxrng = (1:80) + 80*(k1-1);
    ipt{k1} = findchangepts(L(idxrng));
    plot(Bn(idxrng), L(idxrng))
    grid
end

Note: The ‘ipt’ indices would be with respect to each section of ‘L(idxrng)’ not the entire ‘L’ vector. To create that, you would have to add the ‘80*(k1-1)’ offset to each set. If you want to do that, create a second set of vectors with those offsets, then concatenate them into one vector of serial ‘ipt’ values.