Size mismatch using reshape in HDL Coder
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Alla am 2 Nov. 2018
Kommentiert: Bharath Venkataraman am 2 Nov. 2018
I have an 8x8 input matrix, since 2D matrices aren't supproted I reshape it to 64x1 for the input and then reshape it back within the function using A=reshape(A, 8, 8); it runs well in Matlab but the code generation spits out this error:
Size mismatch (size [64 x 1] ~= size [8 x 8]). The size to the left is the size of the left-hand side of the assignment.
What's odd is that the problem seems to have came out of nowhere because I'm almost certain It was working well and I didn't change anything then it just started to error.
Could you try assigning the value to a different variable rather than back to A. Ar = reshape(A,8,8);
use Ar in the code below.
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