How to write coding for the following problem
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How to calculate the following loop
y(1)=x;
for i=1:3
y(i+1)=z(i)+y(i);
i=i+1;
end
Ans=z(1)+z(2)+z(3)+3*x
1 Kommentar
Kevin Claytor
am 4 Jul. 2012
You don't need the "i=i+1" statement - the increment is contained next to the for statement;
for i = start:increment:end
disp(i);
i = i+1;
end
So for start = 1, increment = 1, end = 3 you would get "1 2 3" For start = 2, increment = 2, end = 7 you would get "2 4 6" Your added "i=i+1" affects everything after it, but then the value for i is re-written when the for loop begins again. For example, try this;
for i = 1:3
disp(i);
i = i+1;
disp(i)
end
Should give you the output; "1 2 2 3 3 4"
Antworten (2)
F.
am 4 Jul. 2012
Hello, I don't understand how you can make i=i+1 in a loop on i !! ;-)
When I see your code, I can write this:
y(1) = x
y(2) = z(1) + y(1) = z(1) + x
y(3) = z(2) + y(2) = z(1) + z(2) + x
y(4) = z(3) + y(3) = z(1) + z(2) + z(3) + x
so:
y(n+1) = sum( z(1:n) ) + x
and not what you wrote:
Ans=z(1)+z(2)+z(3)+3*x
Where is the problem ....
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