Filter löschen
Filter löschen

Minimize φ using mathematical optimization toolbox

3 Ansichten (letzte 30 Tage)
Vanshika Singh
Vanshika Singh am 24 Okt. 2018
Kommentiert: Vanshika Singh am 4 Nov. 2018
x(t) is a matrix which is a function of t, of order Nx2
The final equation is required in be variable form (variables- φ, n, N, x, t0, tf) here, t0 = initial point on 2D plane (time 0 sec.) tf= final point on 2D plane (time when robot reaches the goal point, x(tf) ) please note that the x(t) is in differential form in the equation mentioned above.
  4 Kommentare
Torsten
Torsten am 25 Okt. 2018
xi_dot(t)=0 for all i minimizes the functional.
Since I don't think that this solution is what you are asking for, my guess is that there are some constraints on the xi that you didn't mention.
Vanshika Singh
Vanshika Singh am 25 Okt. 2018
Sorry for not mentioning the constraints.
these are the equations-

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Erik Keever
Erik Keever am 25 Okt. 2018
Since you say you can evaluate the functional,
zeta = functional(x_i(t); phi, gamma)
It sounds like all you need to do is make an anonymous handle to evaluate it given the phi/gamma parameters and pass that to one of the optimization toolbox's blackbox minimizers, which will in turn look for gamma and phi that minimizes zeta.
Since you haven't stated any constraints I might suggest to use fminunc rather than fmincon, but it's not exactly clear what the question is: Are we actually seeking x_i(t) (i.e. solving the functional calculus extremization problem numerically), or phi, or both simultaneously?
  2 Kommentare
Vanshika Singh
Vanshika Singh am 2 Nov. 2018
I have listed the constraints above, please help. we are not much concerned with phi. We are looking for minimizing gamma
Vanshika Singh
Vanshika Singh am 4 Nov. 2018
We wish to minimize phi , which is a function of x(t)_dot and its transpose.

Melden Sie sich an, um zu kommentieren.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by