Getting an error "Matrix Dimension must agree" in matlab program. Help me.
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for epsilon3=-1:1:1
N_dash(1)=-0.5+epsilon3;
N_dash(2)=-2*epsilon3;
N_dash(3)=0.5+epsilon3;
end
for i=-1:1:1
epsilon3=(i)
lx=(epsilon3-0.5)*x(1)-(2*epsilon3)*x(2)+(epsilon3+0.5)*x(3);
mx=(epsilon3-0.5)*y(1)-(2*epsilon3)*y(2)+(epsilon3+0.5)*y(3);
nx=(epsilon3-0.5)*z(1)-(2*epsilon3)*z(2)+(epsilon3+0.5)*z(3);
%%Jacobian Factor
s=sqrt(((lx)^2)+(((mx)^2)+(((nx)^2))));
end
%%Tangent vector (ey) about y dirsction ly=(x(5)-x(2)); my=(y(5)-y(2)); ny=(z(5)-z(2));
lve=sqrt(((ly)^2)+((my)^2)+((ny)^2)); %%vertical length of element ey = [ly; my; ny] / lve; for i=1:8 B_matrix(1,i)=1/s*repmat(N_dash, 3, 1) .* repelem(ey, 3, 1) %(ERROR HERE)
end
x,y,z are constant values like 0.2132,0.9876 etc.
Error using .*
Matrix dimensions must agree.
Error in practisee2 (line 309)
B_matrix(1,i)=1/s*repmat(N_dash, 3, 1) .* repelem(ey, 3, 1)
1 Kommentar
Walter Roberson
am 24 Okt. 2018
Is it possible that you want to compute the dot product?
Antworten (1)
Haritha
am 23 Okt. 2018
0 Stimmen
Hi Try this B_matrix(1,i)=1/s.*repmat(N_dash, 3, 1) .* repelem(ey, 3, 1)
5 Kommentare
Virajan Verma
am 23 Okt. 2018
Virajan Verma
am 23 Okt. 2018
Torsten
am 23 Okt. 2018
Before the line
B_matrix(1,i)=...
insert the lines
size(repmat(N_dash, 3, 1))
size(repelem(ey, 3, 1))
in your code and take a look at what MATLAB tells you in the output window.
If the sizes of the two arrays differ, MATLAB will complain about "Matrix dimensions must agree". Furthermore, since B_matrix(1,i) is a single scalar, the two sizes must be 1. Since this is not the case, you will get an error anyhow.
Best wishes
Torsten.
Virajan Verma
am 24 Okt. 2018
Torsten
am 24 Okt. 2018
If N_dash has size 3x3, then repmat(N_dash,3,1) will produce an error. If ey has size 9x1, then repelem(ey,3,1) has size 27x1. No chance for elementwise multiplication.
And note again that the right-hand side ... of an assignment of the form
B_matrix(1,i) = ...
must have size 1x1.
Best wishes
Torsten.
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