Decimal increments in a for loop

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nth24601
nth24601 am 21 Okt. 2018
Bearbeitet: Walter Roberson am 24 Okt. 2018

Hello, I am trying to make a for loop in which i goes up by decimal increments and for each value of i (1, 1.1, 1.2, 1.3) a different value for a function is calculated and stored. I am aware that there are such threads already existing but none of them actually seem to solve the problem. My code so far looks like that:

z = 1:0.1:100;
for i=1:length(z)
  if i<10
      y(:,i) = function of i
  elseif (10<=i)&&(i<50)
      y(:,i) = another function of i
  elseif (50<=i)&&(i<=100)
      y(:,i) = another function of i
  end
end

The problem with that is that i does not actually go up by 0.1, it goes up by 1, and the function calculates values for i equal to 1,2,3,... etc I want it to take i=1, calculate the value of y for that, then take i=1.1, calculate the value for that etc.

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 22 Okt. 2018
Bearbeitet: Walter Roberson am 24 Okt. 2018
  1 Kommentar
nth24601
nth24601 am 24 Okt. 2018
Thanks, the answers in this link helped me solve this problem.

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Weitere Antworten (1)

madhan ravi
madhan ravi am 21 Okt. 2018
z = 1:0.1:100;
for i=1:length(z)
if z(i)<10
y(:,i) = function of i
elseif (10<=z(i))&&(z(i)<50)
y(:,i) = another function of i
elseif (50<=z(i))&&(z(i)<=100)
y(:,i) = another function of i
end
end
  3 Kommentare
nth24601
nth24601 am 22 Okt. 2018
This gets close to the answer but it doesnt make i go by increments of 0.1, it only creates a 1000 entries for i, but i keeps going up by 1. I need the final value of i to be 100. Thank you for the answer though.
madhan ravi
madhan ravi am 22 Okt. 2018
You can’t index 0.1 as an index , See indexing in MathWorks Page you will understand only an integer can be used as an index not a float

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