Code for equation with ln
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How can i Code it?
u=0.23 y=0.3 v=0.00001
u/u’=5*log(u’*y/v)-3.05
u’=?
I need to find the value of u’.
![](/matlabcentral/answers/uploaded_files/137360/NP.png)
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Antworten (1)
Star Strider
am 21 Okt. 2018
Try this:
u=0.23;
y=0.3;
v=0.00001;
fcn = @(ustar,u,y,nu) 5*log(ustar.*y/nu)- 3.05 - u/ustar;
ustar = fsolve(@(ustar)fcn(ustar,u,y,v), 1)
ustar =
0.00918407730971717
2 Kommentare
Star Strider
am 21 Okt. 2018
I already posted all the code that is needed to solve this problem.
You need to have the Optimization Toolbox installed to use fsolve.
You will have fminsearch regardless, so try using fminsearch on the norm of ‘fcn’:
ustar = fminsearch(@(ustar)norm(fcn(ustar,u,y,v)), 1)
ustar =
0.00918426513671787
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