Fastest way to create N by 1 matrix which contain lots of zero without using for loop
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Jinsu Kim
am 12 Okt. 2018
Kommentiert: Jinsu Kim
am 12 Okt. 2018
I want to express n x 1 matrix, X
X = [ a; a; a; a; b; 0; 0; 0; b; 0; 0; 0; (...) b; 0; 0; 0; b; 0; 0; 0; c; c; ] ("b; 0; 0; 0;" block is repeated N times)
What I first design is that:
A = a * ones(4,1) ; B = zeros(4,1); B(1) = b ; C = c * ones(2,1); X = [ A ; B ; B ; (...) B ; B ; C ] ;
But the problem is that I cannot set a number of center block. How can I code it?
Thanks in advance :D
0 Kommentare
Akzeptierte Antwort
OCDER
am 12 Okt. 2018
a = 1;
b = 2;
c = 3;
N = 10;
D = [repelem(a, 4, 1);
repmat([b; 0; 0; 0], N, 1);
repelem(c, 2, 1)];
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!