How to generate numbers from probability mass function?

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Clarisha Nijman
Clarisha Nijman am 9 Okt. 2018
Beantwortet: PARTHEEBAN R am 22 Mai 2021
Hallo,
Given a probability mass function defined as P(X=3)=0.2, P(X=7)=0.3 and P(X=10)=0.5, I want to generate randomly 30 numbers (values for X) with this probability mass function as base. But I really have no idea how and where to start.
Can somebody help me?
Thank you in advance

Akzeptierte Antwort

Torsten
Torsten am 9 Okt. 2018
Bearbeitet: Torsten am 9 Okt. 2018
n = 30;
X = zeros(n,1);
x = rand(n,1);
X(x <= 0.5) = 10;
X(x > 0.5 & x <= 0.8) = 7;
X(x > 0.8) = 3;
  3 Kommentare
Torsten
Torsten am 10 Okt. 2018
For an explanation, see
https://stats.stackexchange.com/questions/26858/how-to-generate-numbers-based-on-an-arbitrary-discrete-distribution

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Weitere Antworten (3)

Bruno Luong
Bruno Luong am 9 Okt. 2018
A more generic method:
p = [0.2 0.3 0.5];
v = [3 7 10];
n = 10000;
c = cumsum([0,p(:).']);
c = c/c(end); % make sur the cumulative is 1
[~,i] = histc(rand(1,n),c);
r = v(i); % map to v values
  1 Kommentar
Clarisha Nijman
Clarisha Nijman am 19 Okt. 2018
This answer works for me the best. I need this to do random column sampling (sampling some columns of a very big matrix A)

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Jeff Miller
Jeff Miller am 20 Okt. 2018

With Cupid you could write:

v = [3 7 10];       % the values
p = [0.2 0.3 0.5];  % their probabilities
rv = List(v,p);     % a random variable with those values & probabilities
n = 10000;
randoms = rv.Random(n,1);  % generate n random values of the random variable
  3 Kommentare
Jeff Miller
Jeff Miller am 20 Okt. 2018
Did you download the Cupid files (see the link in my answer)? These define the List class (which handles the cumulative distribution behind the scene). Do the other Cupid demos run correctly?
Well, Cupid may be overkill for your problem, but it does have a lot of flexibility.
Clarisha Nijman
Clarisha Nijman am 20 Okt. 2018
Ok, tnx Jeff, I'll check it!

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PARTHEEBAN R
PARTHEEBAN R am 22 Mai 2021
A random variable X has cdf F(x) = { 0 , if x < − 1 a(1 + x ) , if − 1 < < 1 1 , if x ≥ 1 . Find (1) the value of a, (2) P(X > 1/4 ) and P ( − 0 . 5 ≤ X ≤ 0 ) .

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