how to delete specific entries (based on a condition) in an array?

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Hi I wrote a small code, which goes as follows: %start of code
a = [0 12 16 13 14 25 12 1 170 172 32 5 171]; for i = 1:length(a); if a(i) < 18 a(i) = []; end end % end of code
The intent is to eliminate those entries which have values less than 18. It gives me two errors. Error One- it doesnt execute the entire length of a, stops in between with an error message that --- ??? Attempted to access a(9); index out of bounds because numel(a)=8.
Error in ==> array_elimination at 7 if a(i) < 18 Error two- It doesnt eliminate all the entries <18, it just eliminates the alternate entries. Thats strange and makes me feel that its a bug in matlab!! Need help

Accepted Answer

Honglei Chen
Honglei Chen on 28 Jun 2012
Edited: Honglei Chen on 28 Jun 2012
You are changing a every time when you found an element less than 18, so when the iteration gets to the original array length, it is out of bound. You can achieve what you want by the following command
a(a<18) = []
  1 Comment
Subrat kumar sahoo
Subrat kumar sahoo on 28 Jun 2012
Perfect, Thanks Honglei, Didnt occur to me :( wasted half a day Thanks again

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