How can we get the solution for an 'exact differential equation' dy/dx=(x^2-y^2)/2*x*y in matlab
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abcdr
am 30 Sep. 2018
Kommentiert: madhan ravi
am 11 Okt. 2018
'exact differential equation'dy/dx=(x^2-y^2)/2*x*y'
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Star Strider
am 30 Sep. 2018
You seem to have omitted the LHS.
dxdt = (x^2-y^2)/2*x*y
dydt = (x^2-y^2)/2*x*y
dxdy = (x^2-y^2)/2*x*y
dydx = (x^2-y^2)/2*x*y
or something else?
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