Another data manipulation question,need some help!

1 Ansicht (letzte 30 Tage)
Xiao Tang
Xiao Tang am 23 Jun. 2012
There are two matrix A and B.
A =
15 4534 0 31
10 0 346 0
10 342 124 11
20 345 0 13
25 73 311 15
15 0 0 14
10 0 153 16
15 532 129 19
20 153 0 0
B =
10 4324 13976 7645
15 7675 3821 14510
20 13198 0 3874
25 4321 4321 4321
According to the first column, replace the rest columns of A with B.
The result should be:
C =
15 7675 3821 14510
10 4324 13976 7645
10 4324 13976 7645
20 13198 0 3874
25 4321 4321 4321
15 7675 3821 14510
10 4324 13976 7645
15 7675 3821 14510
20 13198 0 3874
I used 2 loops(shown as follows) to get the result. But I was wondering if there is an easier way.
C(:,1) = A(:,1);
for i = 1: length(A)
for n = 1:length(B)
if A(i,1) ==B(n,1)
C(i,2:4) = B(n,2:4);
end
end
end
Any suggestion is welcomed!

Akzeptierte Antwort

Walter Roberson
Walter Roberson am 23 Jun. 2012
[tf, idx] = ismember( A(:,1), B(:,1) );
A(tf,:)= B(idx(tf), :);
  1 Kommentar
Xiao Tang
Xiao Tang am 23 Jun. 2012
Thanks @Walter Roberson. The ismember function and logical index should be more efficient than my loop!

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Andrei Bobrov
Andrei Bobrov am 23 Jun. 2012
[b b b] = unique(A(:,1));
C = B(b,:)
  1 Kommentar
Xiao Tang
Xiao Tang am 24 Jun. 2012
What can I say, man. You gave me great answers to all my questions.Thanks a million!

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by