Create a vector z with 1000 elements generated by the rand-function. The generated values must have a mean value of 0.5 (mean(0.5)). And a standard deviation of sqrt(1/100*12), (std(x)).
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Vetle Normann
am 7 Sep. 2018
Kommentiert: Rik
am 28 Jun. 2023
So my task is to determine mean of an random vector to be set to 0.5. And the set standard deviation to be sqrt(1/100*12)
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Adam
am 7 Sep. 2018
And what have you done so far. I assume you have searched the Matlab help for functions such as 'rand' and followed the links from there to the other random number generation functions.
Rik
am 28 Jun. 2023
What makes you think after almost 5 years that this question is unclear? Please provide an explanation in a comment.
I have removed your flag and will copy the question below.
Create a vector z with 1000 elements generated by the rand-function. The generated values must have a mean value of 0.5 (mean(0.5)). And a standard deviation of sqrt(1/100*12), (std(x)).
So my task is to determine mean of an random vector to be set to 0.5. And the set standard deviation to be sqrt(1/100*12)
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Cesar Antonio Lopez Segura
am 7 Sep. 2018
Hi all
Here the code:
mu = 0.5;
sigma = 0.3464;
z = mu + randn(1,1000)*sigma
STDcalculated = std( z )
MuCalculated = mean( z )
3 Kommentare
Cesar Antonio Lopez Segura
am 7 Sep. 2018
Hi Vetle,
Using this values you can minimize your error:
mu = 0.50329141240781;
sigma = 0.347330944035507;
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Torsten
am 7 Sep. 2018
Bearbeitet: Torsten
am 7 Sep. 2018
0.5*(a+b) = 0.5
1/12*(b-a)^2 = 0.12
Solve for a and b.
This will give you the interval [a b] for which you must generate uniformly distributed random numbers.
Then you can use the rand-function as
z=a+(b-a)*rand(1000,1)
Best wishes
Torsten.
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