Take a matrix of integers and convert to a binary matrix

I have a matrix of random integers, but the rows are sorted numerically from 1-10. I would like to convert these integers into positions of a binary matrix, so each integer in the matrix represents a position labelled 1 in the binary matrix.

e.g As a smaller scale example, (cause my final integer matrix is very large) Say I have a matrix given by

     1     6     8
     3     5     7
     2     4     9

I would want this converted to a 10 x 3 matrix that reads

     1     0     0     0     0     1     0     1     0     0
     0     0     1     0     1     0     1     0     0     0
     0     2     0     1     0     0     0     0     1     0

Many thanks

Answer 1

[Akira Agata]

One simple and straight-forward way is using for-loop, like:

A = [1 6 8; 3 5 7; 2 4 9];
B = zeros(3,10);
for kk = 1:3
  B(kk,A(kk,:)) = 1;
end

The result is:

>> B
B =
   1     0     0     0     0     1     0     1     0     0
   0     0     1     0     1     0     1     0     0     0
   0     1     0     1     0     0     0     0     1     0