Basic Function that Prompts User and then Calculates Accordingly

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shiffraw dagnechaw
shiffraw dagnechaw am 22 Aug. 2018
Beantwortet: Image Analyst am 24 Aug. 2018
I'm trying to create a function that gives the user a prompt box that asks the user to choose subtraction or division. This is just a very basic version of what I'm trying to do. I'll paste my code below.
function[result1] = calculate1(x,y)
z = inputdlg({'Subtraction or Division'})
if z == 'subtraction'
x + 1
else
y + 1
end
end
  2 Kommentare
Rik
Rik am 22 Aug. 2018
Your output is not defined in this function, and you are using == instead of strcmp, which will likely result in unintended behavior.
Wycliff Dembe
Wycliff Dembe am 24 Aug. 2018
In addition to using strcmp and defining result1 in the function you can also consider abstracting the input if there are only two or few input choices by creating question dialog box to avoid the case sensitivity and other user input errors. Ref: https://www.mathworks.com/help/matlab/ref/questdlg.html

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Antworten (2)

Walter Roberson
Walter Roberson am 24 Aug. 2018
inputdlg() returns a cell array of character vectors.
z = inputdlg({'Subtraction or Division'});
if strcmpi(z{1}, 'subtraction')
...
end
You should also consider using menu()
  1 Kommentar
Steven Lord
Steven Lord am 24 Aug. 2018
I second Walter's recommendation to use menu. If you must use inputdlg instead of menu (you're trying to complete a homework assignment that specifically instructs you to use inputdlg, for example) I recommend using a switch statement instead of an if statement. See the first example on the switch documentation page for a demonstration of switch, case, and otherwise.

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Image Analyst
Image Analyst am 24 Aug. 2018
Use questdlg():
promptMessage = sprintf('What do you want to do?');
titleBarCaption = 'Which Operation?';
buttonText = questdlg(promptMessage, titleBarCaption, 'Subtraction', 'Division', 'Quit', 'Subtraction');
if contains(buttonText, 'Quit')
% Bail out.
return;
elseif contains(buttonText, 'Subtraction')
% Do your subtraction code.
else
% Addition code...
end

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