problem with frequency domain using fft on raw data
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
I have a problem in my MATLAB program. I'm trying to find a cutoff frequency to create a low pass filter for compass data. I'm trying to go from the time domain to the frequency domain and find an Fc, so I used the FFT but it seems that's it's nor working.
This is what i have done:
if true
fs=1500;
dataset=xlsread('data.xlsx','Feuil1','A1:A363');
t=1:length(dataset);
L=length(dataset);
z=fft(dataset);
P2 = abs(z/L);
P1 = P2(1:L/2+1);
P1(2:end-1) = 2*P1(2:end-1);
f = fs*(0:(L/2))/L;
subplot(2,2,4)
plot(f,P1)
title('frequenciel')
xlabel('f(hz)');
ylabel('p1(f)');
end
but i have found something weird. wish is not what i was expencting
3 Kommentare
dpb
am 22 Aug. 2018
Bearbeitet: dpb
am 22 Aug. 2018
You only sampled at 1500 Hz (fs=1500) according to your code so Nyquist frequency is 750 Hz.
The response of the sensor will depend on the frequency of the energy content of the input to it; "bandwidth" only means it is capable of responding up to that frequency (probably with some documented attenuation value) but you would have to sample at least 2X that frequency to see it and actually by 3-4X that to really reproduce the input well owing to Nyquist.
The FFT "knows nuthink!" about what the actual sampling frequency is; it is immaterial to the algorithm; the frequency for analysis/presentation is totally dependent upon what you say your sampling frequency was and there's absolutely no way to determine that from just the sampled data itself.
Antworten (1)
Siehe auch
Kategorien
Mehr zu Filter Analysis finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!