how to find out inverse of matrix?

T=[1 0 0 0 0 0; 0 m^2 n^2 m*n 0 0; 0 n^2 m^2 -m*n 0 0; 0 -2*m*n 2*m*n m^2-n^2 0 0; 0 0 0 0 m -n; 0 0 0 0 n m];

Answer 1

[Stephan]

Hi,

syms m n
T=[1 0 0 0 0 0;...
    0 m^2 n^2 m*n 0 0;...
    0 n^2 m^2 -m*n 0 0;...
    0 -2*m*n 2*m*n m^2-n^2 0 0;...
    0 0 0 0 m -n;....
    0 0 0 0 n m];
Tinv = inv(T)

check if correct with:

E = simplify(T*Tinv)

gives the expected identity matrix.

Best regards

Stephan

[MUKESH JAAT]

THANKS SIR for solving my problem

[GOVIND PRASAD PANDIYA]

thanks