Inverse Fourier Transformation with a function in the exponent

2 Ansichten (letzte 30 Tage)
Shoaibur Rahman
Shoaibur Rahman am 1 Aug. 2018
Bearbeitet: Shoaibur Rahman am 1 Aug. 2018
I have a signal x[n] with it's Fourier Transform X[k]. I want a frequency-warped signal (x_warp[n]) by taking the inverse Fourier of X[k], with a warping function fun. I know the fun will be somehow incorporated to the exponent of original inverse Fourier e^(j*2*pi*k*n/N)
So far, I have the following code:
x_hat = 1/N * X(1:N/2+1) * exp(1j*fun'/Fs*2*pi*(0:N-1))
x_warp = 2*real(x_hat)
Fs=Sampling frequency. Could you please tell me if the expression in the exponent is correct or not? I.E. what will be exp(???) in the above code?
Thanks in advance!

Antworten (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by