How can I fix the code?
Info
Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.
Ältere Kommentare anzeigen
I'm trying to calculate the sum of f(z1^i,z2^j) for i,i=1:2m and x1,x2 are chosen before (are nodes). Here is my code in Matlab
% code
k=5;r0=0.5; M=1000; m=100; h=r0/m;
ui=@(x,y) exp(5i*y);
a=@(x,y)( 0.01*exp(1-(0.25/(0.25-x.^2-y.^2))).*(x.^2+y.^2 < 0.25)+0.*( x.^2+y.^2 >=0.25));
% a=0.01*exp(1-(0.25/(0.25-x^2-y^2) if x^2+y^2 < 0.25 and a=0 otherwise.
f=@(x1,x2,y1,y2) -1i.*k.^2./4.*besselh(0,sqrt((x1-y1).^2+(x2-y2).^2)).*a(y1,y2).*ui(y1,y2);
s=0;
for p=1:2*m
x1=-r0+p*h;
for q=1:2*m
x2=-r0+q*h;
for i=1:2*m
z1=-r0+(i/2)*h;
for j=1:2*m
z2=-r0+(j/2)*h;
s=s+f(x1,x2,z1,z2);
disp(s);
disp(f(x1,x2,z1,z2));
end
end
end
Matlab can't show the results of 's' but can show the results of 'f(x1,x2,z1,z2)'. How can I fix the code?
2 Kommentare
Walter Roberson
am 30 Jul. 2018
What happens if you try to display s? Is there an error message?
Anh Thu
am 31 Jul. 2018
Antworten (1)
OCDER
am 30 Jul. 2018
For some reason, you're getting a NaN + NaNi, a complex imaginary NaN. Try to skip these, otherwise s will just become NaN + NaN*i.
% code
k=5;r0=0.5; M=1000; m=100; h=r0/m;
ui=@(x,y) exp(5i*y);
a=@(x,y)( 0.01*exp(1-(0.25/(0.25-x.^2-y.^2))).*(x.^2+y.^2 < 0.25)+0.*( x.^2+y.^2 >=0.25));
% a=0.01*exp(1-(0.25/(0.25-x^2-y^2) if x^2+y^2 < 0.25 and a=0 otherwise.
f=@(x1,x2,y1,y2) -1i.*k.^2./4.*besselh(0,sqrt((x1-y1).^2+(x2-y2).^2)).*a(y1,y2).*ui(y1,y2);
s=0;
for p=1:2*m
x1=-r0+p*h;
for q=1:2*m
x2=-r0+q*h;
for i=1:2*m
z1=-r0+(i/2)*h;
for j=1:2*m
z2=-r0+(j/2)*h;
Out = f(x1,x2,z1,z2);
if ~isreal(Out); continue; end
s=s+Out;
disp(s);
disp(Out);
end
end
end
end
Diese Frage ist geschlossen.
Produkte
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!