Ältere Kommentare anzeigen
Dear all, I am sorry for this basic question, but even I have some experience with matlab, I am not able to understand why I cannot display a 3D graph with a set of data X,Y,Z below.
X = (1:1:5)'; % column vector of Param 1
Y = (1:1:10)'; % column vector of Param 2
Z = sin((1:1:50))'; % example of 1D data, but in real case it is point by point (not a function like sin(x,y), cos or any).
shape_Z = reshape(Z, length(X), length(Y));% in 2D representation
I have 1D x-axis parameter, 1D y-axis parameter, and Z is also 1D listing the associated data. In fact Z is reshaped to shape_Z in 2D to have a better understanding of the value for each (X,Y) parameters, as it is not intuitive with Z in 1D.
2 Kommentare
madhan ravi
am 30 Jul. 2018
Bearbeitet: madhan ravi
am 30 Jul. 2018
It’s because they are independent of each other, it means it’s three dimensional arguments in 4 dimensional space and matlab is only capable of 3 dimensional space.
laurent jalabert
am 30 Jul. 2018
Akzeptierte Antwort
Weitere Antworten (0)
Kategorien
Mehr zu Surface and Mesh Plots finden Sie in Hilfe-Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!