counting the correct interval and stop at the end of it

Pd = 480; inter = 18; Cap = 200; hrs = 8640; initial = Cap; yyyy(1) = initial; yyy(1) = 0;

for e_ref = Pd:Pd:hrs for t=1:inter

     if Pd(Pd >= 72 & Pd < 120) 
        yyy(t+1) = ((-0.00005667*e_ref(t) + 100)/100);
        yyyy(t+1) =  yyy(t+1)*Cap;
         e_ref(t+1) = e_ref(t) + Pd;

               elseif Pd == 480  
                  yyy(t+1) = ((-0.00008999*e_ref(t) + 100)/100);  
                  yyyy(t+1) =  yyy(t+1)*Cap;  
                  e_ref(t+1) = e_ref(t) + Pd;
      end
  end    
end

[KALYAN ACHARJYA]

error in the code, pls provide the correct code, so that user help you easily.

Answer 1

[KALYAN ACHARJYA]

%insert the following code within for loop, when Pd becomes 480, the loop execution stop

if Pd==480
  return;
end

[Gali Musa]

i have edited the sample code and my question is that the code runs but instead to use e_ref = 480 960 1440 2400 ....................... 8160 8640. The code uses 8640 9120 9600 .......................17280... how can i adjust it to pick only the first intervals...

[Gali Musa]

i have sorted out the problem..... Thank you

[KALYAN ACHARJYA]

OK, Unable to a response you on time.