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Going from Euler's method to trapezoidal rule

1 Ansicht (letzte 30 Tage)
Chloe Keller
Chloe Keller am 15 Jul. 2018
Beantwortet: Swaraj am 9 Feb. 2023
I used Euler's Method to solve y'= 1−t+4y with y(0) = 1 on the interval [0, 2], h = 0.01. I posted my code below. How would I edit this code to solve the same problem using the Trapezoidal Rule?
if true
syms t y
f=@(t,y) 1-t+4.*y;
t=0;
y=1;
h=.01;
n=(2-0)/h;
for i=1:n
m=f(t(i),(y(i)));
y=[y, y(i)+m*h]; %y(i+1)=y(i)+m*h
t=[t, t(i)+h]; %t(i+1)=t(i)+h
end
for i=1:length(t)
fprintf('%5.4f | %5.4f\n',t(i),y(i))
end
end
  2 Kommentare
DINU ANDREEA-EMILIA
DINU ANDREEA-EMILIA am 3 Jun. 2020
Did you find the answer to your question? Cause i have to do the exact same thing

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Antworten (1)

Swaraj
Swaraj am 9 Feb. 2023
You would have to modify the calculation of the intermediate value m as follows:
if true
syms t y
f=@(t,y) 1-t+4.*y;
t=0;
y=1;
h=.01;
n=(2-0)/h;
%Changed Part Start
for i=1:n
m1 = f(t(i),y(i));
m2 = f(t(i) + h/2, y(i) + m1*h/2);
y = [y, y(i) + m2*h];
t = [t, t(i) + h];
end
%Changed Part End
for i=1:length(t)
fprintf('%5.4f | %5.4f\n',t(i),y(i))
end
end

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