Loop through images in GUI

2 Ansichten (letzte 30 Tage)
Sophie Lis
Sophie Lis am 13 Jul. 2018
Beantwortet: Cris LaPierre am 9 Apr. 2019
I have a cell array of images I am trying to loop through in a GUI using a 'NEXT' button, with two images on the screen at the same time. I have 9 images, each three are a series, and I have 3 series', such that I want to view 1 and 2, and 2 and 3, but not 3 and 1, which would be next in the list. I am having trouble coding this, so any help would be very much appreciated!
function next_block_Callback(hObject, eventdata, handles)
handles.curr_im_fig = handles.curr_im_fig+1;
if mod(handles.curr_im_fig,(handles.maxblock))~=0
p1 = handles.curr_im_fig;
p2 = handles.curr_im_fig+1;
else
p1 = handles.curr_im_fig +2;
p2 = handles.curr_im_fig + 3;
end
imshow(handles.images_fig{handles.curr_im_fig},'parent',handles.axes1);
imshow(handles.images_fig{(handles.curr_im_fig)+1},'parent',handles.axes2);
guidata(hObject,handles)
  1 Kommentar
Adam
Adam am 13 Jul. 2018
You don't appear to be using your p1 and p2. I assume these should be in the imshow command instead of the handles.curr_im_fig stuff.

Melden Sie sich an, um zu kommentieren.

Antworten (1)

Cris LaPierre
Cris LaPierre am 9 Apr. 2019
Unsure what is suppose to happen when transitioning 3->4, 6->7, and 9->1, but I'd do something like this
function next_block_Callback(hObject, eventdata, handles)
% if handles.curr_im_fig is 3,6, or 9
if mod(handles.curr_im_fig,3)==0
if handles.curr_im_fig >= 9
% Reset count to 0
handles.curr_im_fig = 0;
end
p1 = handles.curr_im_fig + 1;
p2 = handles.curr_im_fig + 2;
handles.curr_im_fig = handles.curr_im_fig + 2;
else
p1 = handles.curr_im_fig;
p2 = handles.curr_im_fig + 1;
handles.curr_im_fig = handles.curr_im_fig + 1;
end
imshow(handles.images_fig{p1},'parent',handles.axes1);
imshow(handles.images_fig{p2},'parent',handles.axes2);
guidata(hObject,handles)
I'll just caution that I haven't tested this.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by