identifying the elements of a cell
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
CLARK KENDRICK GO
am 10 Jul. 2018
Kommentiert: Sammit Jain
am 10 Jul. 2018
I have a 700x8 cell, with each cell having a matrix 6x2 in size. I want to get the first row of each cell. How do I perform this?
0 Kommentare
Akzeptierte Antwort
Mandeep Singh
am 10 Jul. 2018
Bearbeitet: Mandeep Singh
am 10 Jul. 2018
From my understanding of the question, you can achieve the required task by following snippet of code:
cnt = 1;
for i = 1:700
for j = 1:8
a(cnt) = C{i,j}(1,:); % stores the first row of each cell in a;
cnt = cnt + 1;
end
end
1 Kommentar
Sammit Jain
am 10 Jul. 2018
I think using a for loop will be slightly computationally expensive in this case.
Weitere Antworten (1)
Sammit Jain
am 10 Jul. 2018
Hi, This seems to be a simple case of cell indexing.
Let's call your original cell array (of cells) 'mainCellArray'
Now, let's have allRowsArray = [mainCellArray{:}] Then, firstRowArray = [allRowsArray{1,:}]
Essentially, we're first re-arranging the contents of the main cell array, stacking them one next to the other, then we just index the first row.
Here's what the code should look like:
allRowsArray = [mainCellArray{:}];
firstRowArray = [allRowsArray{1,:}]
Hope this helps. If in case you want to pick a different combination of rows/columns, then just try to transpose these concatenations and see if you get what you want.
Cheers.
0 Kommentare
Siehe auch
Kategorien
Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!