What would be the way to use one 3D array as index for other 3D array?
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Mantas Vaitonis
am 4 Jul. 2018
Kommentiert: Mantas Vaitonis
am 4 Jul. 2018
Hello, I have two 3D arrays a (3x5x4) and o (1x5x4). What I would like to achieve is to use o array as index for a. The struggle is when I use the function below it would take whole o array when creating new array x (1x5x4), maybe anyone has any idea. I thought about pagefun, but it works with only predefined functions.
a=rand(3,5,4)
o= cat(3,[2 5 1 2 4],[2 5 3 1 5],[2 2 2 4 4],[2 3 1 5 4])
x=a(2,o,:)
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Stephen23
am 4 Jul. 2018
The simplest solution is to use a temporary variable:
>> tmp = a(2,:,:);
>> x = tmp(o)
Another option would be to convert the subscript indices into linear indices, but this is not so trivial.
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Stephen23
am 4 Jul. 2018
Bearbeitet: Stephen23
am 4 Jul. 2018
@Mantas Vaitonis: convert the subscript indices into linear indices:
>> a = rand(3,5,4)
a =
ans(:,:,1) =
0.619297 0.782286 0.293458 0.489529 0.063580
0.727413 0.462825 0.712196 0.129529 0.010375
0.535980 0.625046 0.098377 0.589341 0.623387
ans(:,:,2) =
0.532375 0.927982 0.581526 0.094430 0.486161
0.931640 0.580941 0.182186 0.314561 0.209293
0.826359 0.040024 0.528289 0.704205 0.360965
ans(:,:,3) =
0.225279 0.708014 0.587027 0.020373 0.792127
0.573342 0.530581 0.896023 0.556469 0.471478
0.795015 0.122115 0.109518 0.890492 0.351620
ans(:,:,4) =
0.082299 0.173384 0.587164 0.179035 0.244157
0.527470 0.635292 0.400517 0.953553 0.631803
0.886819 0.880137 0.526968 0.197963 0.232092
>> o = cat(3,[2,5,1,2,4],[2,5,5,3,4],[3,5,4,2,4],[2,1,1,1,4]);
>> S = size(a);
>> [R,~,P] = ndgrid(2,1:S(2),1:S(3)); % 1st input 2 -> row.
>> x = a(sub2ind(S,R,o,P))
x =
ans(:,:,1) =
0.462825 0.010375 0.727413 0.462825 0.129529
ans(:,:,2) =
0.580941 0.209293 0.209293 0.182196 0.314561
ans(:,:,3) =
0.896023 0.471478 0.556469 0.530581 0.556469
ans(:,:,4) =
0.635292 0.527470 0.527470 0.527470 0.953553
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