Info
Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.
How to fix this loop?
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
C = {1,2,3,1,4,6};
%for i = 1:length(C)
List = cell(size(C)); %creating empty list
for i = 1:length(C)
if isequal(C{i}, 1)
List(1) = C(i);
else
List(2) = C(i);
end
end
I GET A OUTPUT OF LIST AS =
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/191586/image.png)
BUT MY OUTPUT SHOULD LOOK LIKE:
IN cell 1 = [1,1]
IN CELL 2 = [2,3,4,6]
THE PROBLEM IS IT STORES THE LAST ELEMENT ENCOUNTERED , BUT IT SHOULD STORE ALL ELEMENTS ENCOUNTERED. HOW TO FIX THIS??
0 Kommentare
Antworten (1)
Stephen23
am 30 Jun. 2018
Bearbeitet: Stephen23
am 30 Jun. 2018
Simpler with a numeric vector:
>> V = [1,2,3,1,4,6];
>> List = {V(V==1),V(V~=1)};
>> List{1}
ans =
1 1
>> List{2}
ans =
2 3 4 6
Note: to get V from the cell array C:
V = [C{:}];
But if you really want to write inefficient code using a loop:
List = cell(1,2);
for k = 1:numel(C)
if isequal(C{k}, 1)
List{1} = [List{1},C{k}];
else
List{2} = [List{2},C{k}];
end
end
which produces exactly the same output less efficiently using more lines of code.
Diese Frage ist geschlossen.
Siehe auch
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!