legend for transparent patch object is opaque ?
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Matilda
am 20 Jun. 2018
Kommentiert: Matilda
am 25 Jun. 2018
Hello,
I create a simple figure with 2 patch objects where one of the patch is opaque and the other one is transparent (with facealpha set to 0.1) :
figure
x = [0 1 1 0];
y = [0 0 1 1];
patch(x,y,'red')
x2 = [3 6 6 3];
y2 = [3 3 6 6];
patch(x2,y2,'green','facealpha',0.1)
legend('red opaque -> OK','green is opaque instead of transparent -> WHY ?')
The legend does not reflect the fact that the green patch is transparent. I really need my legend to show if the patch is transparent or opaque. Is there a work around ?
Thanks !
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Ameer Hamza
am 23 Jun. 2018
The problem is actually caused by the Rendrer of the figure object. In R2018a opengl seems to make the legend entries transparent, but in prior versions, you need to switch to 'painters' renderer to get this behavior. For example, try the following
f = figure;
f.Renderer = 'painters';
x = [0 1 1 0];
y = [0 0 1 1];
patch(x,y,'red')
x2 = [3 6 6 3];
y2 = [3 3 6 6];
patch(x2,y2,'green','facealpha',0.1)
legend({'red opaque -> OK','green is opaque instead of transparent -> WHY ?'}, 'Box', 'off')
2 Kommentare
Walter Roberson
am 23 Jun. 2018
Traditionally only opengl supported transparency, but R2014b added transparency for painters
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Yun Guo
am 22 Jun. 2018
It is not very clear if you want green patch to be transparent, legend to be transparent, or both.
'facealpha' does work as expected. See example below.
- I changed the green patch's size so it overlaps with red patch to show transpareny works.
- I also removed legend box, so legend looks transparent.
figure
x = [0 1 1 0];
y = [0 0 1 1];
patch(x,y,'red');
x2 = [0.5 2 2 0.5];
y2 = [0.5 0.5 2 2];
patch(x2,y2,'green','facealpha',0.3)
l = legend('red opaque -> OK','green is opaque instead of transparent -> WHY ?');
set(l, 'Box', 'off')
5 Kommentare
Ameer Hamza
am 22 Jun. 2018
I am trying on R2018a. Since you have R2017b, which I cannot try at the moment. But to correctly check the opacity move the legend over the red portion like this
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