How to convert datetime vector to military time
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Asher Zaidi
am 18 Jun. 2018
Kommentiert: Stephen23
am 5 Jul. 2018
This is my code:
files = dir('*.xlsx');
for i=1:10
[~, ~, raw] = xlsread(files(i).name);
rawm = raw(5:6,1);
rawmd = cell2mat(rawm(1));
rawmt = cell2mat(rawm(2));
s = strcat(rawmd(31:40),rawmt(30:38));
ds(i) = datetime(s)
end
It produces a vector that looks like this:
ds'
ans =
10×1 datetime array
14-Feb-2018 11:34:16
15-Feb-2018 12:34:58
15-Feb-2018 01:35:04
15-Feb-2018 02:35:26
15-Feb-2018 03:35:52
15-Feb-2018 04:35:59
15-Feb-2018 05:36:05
15-Feb-2018 06:36:14
15-Feb-2018 07:36:41
15-Feb-2018 08:36:48
How can I change the format of the datetime array to military time so that the times may appear in chronological order?
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Akzeptierte Antwort
Stephen23
am 18 Jun. 2018
Bearbeitet: Stephen23
am 5 Jul. 2018
"How can I change the format of the datetime array to military time so that the times may appear in chronological order?"
You don't need to: the Format of datetime objects relates to how the datetime is displayed, and is unrelated to how it is stored internally, so changing how it looks does not change how it will be sorted. If you want chronological order just apply sort and see what happens:
sort(ds)
If you want to change how the datetime is displayed then you can change its Format property. The ISO 8601 date standard is the best to use, as is guarantees chronological order when sorted by character:
T = datetime(...);
T.Format = 'yyyyMMddHHmmss';
3 Kommentare
Peter Perkins
am 5 Jul. 2018
Stephen, I think maybe you meant (H vs. h)
T.Format = 'yyyyMMddHHmmss';
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