Operations between every 2 different elements in a cell?

Hi all,
I have a cell like this:
K>> ur
ur =
4×3 cell array
{[1]} {'-1 -1'} {1×201 cell}
{[2]} {'1 -1' } {1×201 cell}
{[4]} {'1 1' } {1×201 cell}
{[3]} {'-1 1'} {1×201 cell}
I'd like to perform some operations between every 2 elements of the 3rd column of ur, manually be like this:
operation(ur{1, 3}, ur{2, 3}) % 1 and 2
operation(ur(1, 3), ur(3, 3)) % 1 and 3
operation(ur(1, 3), ur(4, 3)) % 1 and 4
operation(ur(2, 3), ur(3, 3)) % 2 and 3
operation(ur(2, 3), ur(4, 3)) % 2 and 4
operation(ur(3, 3), ur(4, 3)) % 3 and 4
The number of cell rows is not limited to 4. Is there a way to do this in a loop? Or whatever automatic? I think I just need to pick the correct index to perform the operation, but how?
Many thanks!
Edit: the operations should all be curly brackets:
operation(ur{m, 3}, ur{n, 3}) % m and n

2 Kommentare

Jan
Jan am 11 Jun. 2018
What is operation? Why do you use curly braces in the first line and round parentheses afterwards?
Xiaohan Du
Xiaohan Du am 11 Jun. 2018
Bearbeitet: Xiaohan Du am 11 Jun. 2018
My mistake, it should all be curly brackets. Operation here is a function in my code, this function takes ur{m, 3} and ur{n, 3} and gives a matrix as a result.

Melden Sie sich an, um zu kommentieren.

 Akzeptierte Antwort

Jan
Jan am 11 Jun. 2018
Maybe you mean:
index = nchoosek(1:4, 2);
for k = 1:size(index, 1)
operation(ur{index(k, 1), 3}, ur{index(k, 1), 3});
end

Weitere Antworten (0)

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Hilfe-Center und File Exchange

Gefragt:

am 11 Jun. 2018

Kommentiert:

am 11 Jun. 2018

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by