extracting the indices of minimum value in a vector, ignoring last value

I need to find the indices of the minimum positive value in a vector, ignoring the last value in the vector. if there is a tie, I need the first value based on indexes.

for example: if R = [120; 70; 50; 0] I want the incides for 50 back (3,1)

if R = [10; 16 ; 10; 30; 10; 0] I want the indices for the first 10 back (1,1)

thanks!!!!

Answer 1

[Paulo Silva]

a=R; %create a copy of R 
%in order to only find positive numbers we do the next line
a(a<=0)=nan; %replace negative numbers and the zero with nan 
[r,c]=find(a==min(a(1:end-1)),1) %find values

alternative and better:

[r,c]=find((R==min(a(1:end-1)))>0,1) %find values

[brittany adam]

Thanks for your help!! question though,

this keeps returning 1,1 for me-

If R = [-10; 2 ; 4; 1; 10; 0]

I want (4, 1) back. How do I stipulate I am just concerned with the positive values?

[Paulo Silva]

i fixed the code, try it now

[brittany adam]

thank you, thank you!! you're awesome :)

[Jan]

@Brittany: Does this mean, that you accept the question? Then please press the corresponding button.