fitlm on timetable: error message

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alpedhuez
alpedhuez am 8 Jun. 2018
Kommentiert: Walter Roberson am 8 Jun. 2018
I try to run fitlm on a time table. I checked dependent and independent variables and got following outputs
ans =
2.5017
1.8388
1.8418
2.0561
5.0655
ans =
17.4631
19.5389
16.5552
15.0083
11.4510
But when I try to run fitlm, I got a following error message:
Error using classreg.regr.FormulaProcessor (line 384)
The model formula contains names not recognized as predictor or response names.
Error in classreg.regr.LinearFormula (line 48)
f = f@classreg.regr.FormulaProcessor(varargin{:});
Error in classreg.regr.TermsRegression.createFormula (line 699)
formula = classreg.regr.LinearFormula(modelDef,varNames,'',intercept,link);
Error in LinearModel.createFormula (line 1388)
formula = classreg.regr.TermsRegression.createFormula(supplied,modelDef, ...
Error in LinearModel.fit (line 1224)
model.Formula = LinearModel.createFormula(supplied,modelDef,X, ...
Error in fitlm (line 121)
model = LinearModel.fit(X,varargin{:});
Error in AAA (line 247)
lm2 = fitlm(T,'VAR1~VAR2');
Please advise.
  3 Kommentare
Walter Roberson
Walter Roberson am 8 Jun. 2018
What are the names of the variables in the timetable ?
alpedhuez
alpedhuez am 8 Jun. 2018
VAR1 and VAR2

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Akzeptierte Antwort

Walter Roberson
Walter Roberson am 8 Jun. 2018
fitlm() specifically tests for table objects, and timetables are not tables. fitlm is defined for tables, datasets, numeric arrays, and tall arrays, but not defined for timetables.
You can use timetable2table() to convert your timetable for use with fitlm.
  2 Kommentare
alpedhuez
alpedhuez am 8 Jun. 2018
Should be fixed in the future release.
Walter Roberson
Walter Roberson am 8 Jun. 2018
You can file an enhancement request. It is not a bug because not all methods that apply to tables also apply to timetables.

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