Have a problem on my code could you help me? URGENT

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Gerard Nava
Gerard Nava am 26 Mai 2018
Kommentiert: Walter Roberson am 26 Mai 2018
a2=28
ctheta3=cos(1:1:360)
stheta3=sin(1:1:360)
a3=39
stheta2=sin(1:1:360)
ctheta2=cos(1:1:360)
s=(a2*ctheta2)+(a3*ctheta3)
e=-((a2*stheta2)+(a3*stheta3))
subplot(3,2,1),plot(s,'c'),xlabel('Posición'),ylabel('Tiempo'),title('Grafica de posición s','FontSize',12)
subplot(3,2,2),plot(e,'r'),xlabel('Posición de e'),ylabel('Tiempo'),title('Grafica de posición e','FontSize',12)
DCt3=diff(ctheta3)
DSt3=diff(stheta3)
DCt2=diff(ctheta2)
DSt2=diff(stheta3)
W3=(a2*DCt2)./(a3*ctheta3)
subplot(3,2,3),plot(W3,'g'),xlabel('Velocidad de theta3'),ylabel('Tiempo'),title('Grafica de velocidad angular de theta3','FontSize',12)
Matrix dimensions must agree.
my problem is when i want to get W3 from the math equations!
  3 Kommentare
Image Analyst
Image Analyst am 26 Mai 2018
No, don't double space code to get it to properly format. Highlight it and THEN click the {}Code icon:

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Image Analyst
Image Analyst am 26 Mai 2018
Usually with diff() people prepend a zero
DCt2 = [0, diff(ctheta2)]

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Gerard Nava
Gerard Nava am 26 Mai 2018
In DCt2 i have 359 elements and in ctheta3 i have 360 elements, how do i arrange the elemnts in 359 in order to be 360, should i add a 1 in its matrix ?, if so , how fo i write that part of the code of DCt2

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