How could i search a text for varying patterns
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Joey Cavale
am 23 Mai 2018
Kommentiert: Joey Cavale
am 23 Mai 2018
Hello, I am trying to search through an excel file looking through model names and only pulling out the option codes.
For Example the excel sheet with the model names would look like: '1010AB-50K-TB' '1010AB-25K-B' '1010AB-100K'
and I want to create a new array with just the option codes (which in this case is AB). So to look something like this:
'AB' 'AB' 'AB'
and so on... the option codes vary from two letters to three letters and vary from A-Z (AB, AE, AF, AAA, ABD). The only consistency in the model names is the four numbers before the option code and the dash after. How do y'all think the best way to do this would be?
4 Kommentare
Paolo
am 23 Mai 2018
I have edited my regex expression, now the first letter will also range from A to Z. Check out my answer down below.
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Paolo
am 23 Mai 2018
Bearbeitet: Paolo
am 23 Mai 2018
For a pattern of two to three letters, starting with any letter (A to Z) and ending with any letter (A to Z) you can use the following code:
expression = '([A-Z][A-Z]?[A-Z](?=-))';
model_names = {'A1010ACZ-50K-AAA' '1010AB-25K-B' '1010AT-100K'};
[tokens] = regexp(cell2mat(model_names),expression,'tokens');
The expression has three elements, all ranging from A to Z (the [A-Z]). The third element is optional (denoted by the question mark). The expression contains a lookahead (?=-) which searches for the dash however does not include it in the tokens.
The code returns:
tokens{:} = {'ACZ'},{'AB'},{'AT'}
5 Kommentare
Paolo
am 23 Mai 2018
Are you working with each model number individually? If so, you can either use:
expression = '([A-Z][A-Z]?[A-Z](?=-)).*'
or even specify once in the function:
[tokens] = regexp(model_names,expression,'tokens','once');
Or are you working with a cell array?
Weitere Antworten (1)
jonas
am 23 Mai 2018
Bearbeitet: jonas
am 23 Mai 2018
Not sure if it's the best way, but the code starts at str(5) and ends at the dash, so this should work
[~,s] = regexp(str, '-', 'match')
out=str(5:s(1)-1)
2 Kommentare
Paolo
am 23 Mai 2018
Unsure as to why you selected this answer. The code is limited in application and will not work if for some reason the codes change format, let's say from
1010AB-50K-TB
to
10105AB-50K-TB
will result in an incorrect output.
5AB
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