Filter löschen
Filter löschen

how to have a loop if for a column in a table

2 Ansichten (letzte 30 Tage)
Jessica Blasco
Jessica Blasco am 14 Mai 2018
Kommentiert: Peter Perkins am 17 Mai 2018
I have a table with many columns... I want to iterate into one column, that have many numbers valores. is there someone that can help me?
the pseudocode is
if table.column > number
table.new_column= 'Ok'
else
table.this_new column='nok'
finally i wil have a new columns with ok and nok depending of the valor of the column

Akzeptierte Antwort

Ameer Hamza
Ameer Hamza am 14 Mai 2018
Bearbeitet: Ameer Hamza am 14 Mai 2018
You don't need a for loop, use arrayfun(),
words = {'nok', 'ok'};
table.newColumn = arrayfun(@(x) words((x>number)+1), table.column);
  3 Kommentare
Jessica Blasco
Jessica Blasco am 14 Mai 2018
ok, this solution works, but i have another question ... in my case, i have 8 types de variables in a column (1..8) for each type i have a value limit,(stored them in a vector) So... limit_value=[ number1, number 2, number 3,....,number 8] i want to evaluate for each type, the value that corresponds in the limit value.
type 1 -> evaluate > number 1
type 2-> evaluate > number 2
....
but i want to have with a loop, it's posible?
thanks!
Ameer Hamza
Ameer Hamza am 14 Mai 2018
It is not clear what you are trying to do but you can access and change values of a table just like a cell array using table{1,1} (first column, first element). Similarly, use can assign as
table{1,1} = 1; % it will assign the value

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Peter Perkins
Peter Perkins am 14 Mai 2018
Ameer's solution works, but arrayfun is really not needed:
words = {'nok', 'ok'};
table.newColumn = words(table.column>number)+1);
But also, a cell array of 'ok' and 'nok' is likely not all the helpful. I'd suggest making a categorical variable:
table.newColumn = categorical(table.column>number,[false,true],{'nok' 'ok});
Like Ameer, I'm not able to fully understand the followup question.
  2 Kommentare
Jessica Blasco
Jessica Blasco am 15 Mai 2018
i have a vector with 8 numbers,so v=[number1, number2,...., number8] In my column i have 8 categories of number, 1..8...
i would like iterate the column such that for each number in the column i can evaluate if this valor is mayor a his position in the vector...
so...
column
1 evaluate number in position 1 of the vector
1 evaluate number in position 1 of the vector 2 evaluate number position 2 of the vector
3 evaluate number in the position 3 of the vector
4 evaluate number in the position 4 of the vector
2 evaluate number in the position 2 of the vector
1 evaluate number in the position 1 of the vector
5 evaluate number in the position 5 of the vector
I would like iterate this table with a loop for, it's posible??
Peter Perkins
Peter Perkins am 17 Mai 2018
I can't follow this. I suggest you open a new thread, with a short, clear example of what you have and what you want.

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Line Plots finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by