Replacing specific rows in a matrix.

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Elaheh
Elaheh on 10 May 2018
Commented: sloppydisk on 10 May 2018
I would like to replace the cells with the following features (those whose types are 9 or 12 and their ID is one of these numbers, 2,11,12). Then I want to replace them with NaN. However, indexB is a vector of 0 s only.
indexB = ( (Type == 9|Type ==12) & (IDscript ==2|IDscript==11|IDscript==12) );
RT(indexB)=NaN;
  2 Comments
Elaheh
Elaheh on 10 May 2018
Yes. It does. Here is my data attached. I had to change xlsx to xls to be able to attach the file.

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Accepted Answer

sloppydisk
sloppydisk on 10 May 2018
a = xlsread('Book2.xls');
indexB = (a(:, 2) == 9|a(:, 2) ==12) & (a(:, 6) ==2|a(:, 6)==11|a(:, 6)==12);
find(indexB)
This gives me 6 indices: 29, 30, 363, 364, 573 and 574.
  2 Comments
sloppydisk
sloppydisk on 10 May 2018
The idea is the same but is mergedData just a 748x6 double? What is the data type of "Type" and "IDscript"?

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More Answers (1)

Elaheh
Elaheh on 10 May 2018
merged file (748*6) is the content of the excel file I sent you. Ive just started using MATLAB. Type= mergedData(:,2); accuracy= mergedData(:,3); RT= mergedData(:,4); TypeScript=mergedData(:,5); IDscript= mergedData(:,6);
  1 Comment
sloppydisk
sloppydisk on 10 May 2018
Yeah that should work. You can attach the script if it's still not working for you.

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