Filter löschen
Filter löschen

Loop plus diff function with non-integers: Feasible?

2 Ansichten (letzte 30 Tage)
Charles Martineau
Charles Martineau am 31 Mai 2012
hi all,
I am not sure if this is easy or not but I am struggling with the following:
Say that I have a vector Xt (10,000*1) of daily stock returns. I built this partition function formula:
for j=1:125;
E=Xt(1:j:end);
EE=diff(E(2:end));
EEE=diff(E(1:end-1));
Sq(j)=sum(abs(EE-EEE).^3);
end;
where j=1:125 is the various intervals that I wish to calculate the difference EE-EEE from the vector Xt. Now, what is the most efficient way for me to calculate the EE-EEE using non integer numbers?
If I construct a new vector as follow:
expo=0:1000;
A=1.1*ones(size(expo));
ddt=A.^expo;
in ddt there are numbers in which I would like to implement rather than 1:125.
(ddt vector looks like [1 1.1 1.21 1.331 1.4641 1.61051 1.771561 1.9487 2.14358]
What's the best way for to achieve this? In my orignal formula, I generate a Sq vector of size 1X125 for integer intervals but I want more numbers therefore I must turn to non-integer numbers.
Thank you very much for the help!

Akzeptierte Antwort

Oleg Komarov
Oleg Komarov am 31 Mai 2012
If I understood correctly, you want to partition non non integer ontervals. Say you want to select Xt every 1.331 step.
Since you have values only at Xt(1), Xt(2) etc... and not on Xt(1.331), Xt(2.662) etc but you still want to get those number then you can interpolate.
  2 Kommentare
Charles Martineau
Charles Martineau am 31 Mai 2012
Yes exactly! Basically the best is for me to generate a new Xt vector with elements 1.331 2.662. ... and then take the diff of this vector.
Oleg Komarov
Oleg Komarov am 31 Mai 2012
Use interp1() to generate the interpolated values of Xt.

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Charles Martineau
Charles Martineau am 31 Mai 2012
If anyone can help... I am really struggling with this one!

Kategorien

Mehr zu Creating and Concatenating Matrices finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by