# Is there a simple approach to adding spaces before and after every number in a cell array, where each cell is a combination of numbers and letters?

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Hans Sunaryanto am 4 Mai 2018
Hello,
I have an [m x n] cell in the range of thousands. For simplicity, let's deal with a 2x3 cell instead. The elements are as follows:
{[123xswqe412]} {[xasdak12399a8s]} {[123123xq13]}
Can you please advise on how I can make it so that the output is as follows:
{[123 xswqe 412]} {[xasdak 12399 a 8 s]} {[123123 xq 13]}
{[qasoasf 1231]} {[asd 11 skka 13551]} {[127 u 8 adkja]}
Any help would be appreciated!
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dpb am 4 Mai 2018
That's almost assuredly a regexpr job but beyond my pay grade to try to write the expression! :)

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### Akzeptierte Antwort

sloppydisk am 4 Mai 2018
Bearbeitet: sloppydisk am 4 Mai 2018
I don't know why I took the time to do this and my function separating the words is super ugly but I think you want something like this:
% string
str = '123xswqe412ew3';
% regular expression to separate string from number
expr = '\d+|\D+';
%create cell with strings
mycell = cell(50, 1);
mycell(:) = {str};
% perform function on cell
mycell(:) = cellfun(@(x)doRegExp(x, expr), mycell, 'UniformOutput', false);
% function to separate strings
function f = doRegExp(str, expr)
ind = regexp(str, expr);
f = str(ind(1):ind(2)-1);
for i = 2:length(ind)-1
a = str(ind(i):ind(i+1)-1);
f = [f, ' ', a];
end
f = [f, ' ', str(ind(i+1):end)];
end
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sloppydisk am 4 Mai 2018
Bearbeitet: sloppydisk am 4 Mai 2018
ind = regexp(str, '\d+[\.]\d+|\D+|\d+', 'match')
I added an extra OR statement basically to check for digits with dots in between. And maybe this match option in regexp is actually an easier way of splitting your string.
Hans Sunaryanto am 4 Mai 2018
Yes it is! Thank you so much!!

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### Weitere Antworten (1)

jonas am 4 Mai 2018
I'll just go ahead and give an alternative answer because I spent way too much time trying to solve this seemingly easy problem :)
clear all;
str='1.23AB.C44444OA43872AX5';
[ind11,ind12] = regexp(str, '\d[A-Za-z]');
[ind21,ind22] = regexp(str, '[A-Za-z]\d');
ind=sort([ind11 ind12 ind21 ind22])
chars=str(ind)
str=regexprep(str,'\d[A-Za-z]','X X')
str=regexprep(str,'[A-Za-z]\d','X X')
ind3=regexp(str,'X')
str(ind3)=chars
I tried solving the problem with '.', as mentioned in the comment. Unfortunately a new bug appeared, where substrings like 21.FP will not be split. Not sure how to solve that though.
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Hans Sunaryanto am 4 Mai 2018
Thank you! That's fine since I don't think I'll ever need a letter immediately after a dot. Thanks again!

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