how to form branch to node incidence matrix by using tree

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Yearuva Srikanth reddy
Yearuva Srikanth reddy am 3 Mai 2018
Bearbeitet: Akbar am 3 Mai 2018
how to form incidence matrix for this graph

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Akbar
Akbar am 3 Mai 2018
Bearbeitet: Akbar am 3 Mai 2018
G = digraph([1 2 2 2 3 4], [4 1 3 4 1 3]);
G.Nodes.Name = {'a' 'b' 'c' 'd'}';
h = plot(G);
labelText = {'6' '3' '2' '4' '5' '1'};
labeledge(h,[1 2 2 2 3 4], [4 1 3 4 1 3],labelText)
I = full(incidence(G));

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