Info
Diese Frage ist geschlossen. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.
Hi, can you help me!!! I 've got a problem when i went to calculate this matrix:
    3 Ansichten (letzte 30 Tage)
  
       Ältere Kommentare anzeigen
    
A= [Aa  0;-Af*Ca  Af]
With
Aa=[-0.01320 0 0 9.8100 0 0 0 0;-0.08560 -0.9903 -241.7000 0 21.7500 0.9504 18.0800 -0.00073;-0.00017 0.0159 -0.9883 0 -0.4850 -0.0323 -3.3200 -0.10450;0 0 1 0 0 0 0 0;0 0 0 0 0 1 0 0;0.08420 0.8897 -3.0300 0 -164.6000 -4.2050 -28.0500 -0.59690;0 0 0 0 0 0 0 1;-0.02920 -0.1723 -5.0970 0 -2.8540 -0.4456 -430.5000 -2.15500];
Af=diag([-10 -10]);
5 Kommentare
Antworten (1)
  James Tursa
      
      
 am 1 Mai 2018
        
      Bearbeitet: James Tursa
      
      
 am 1 Mai 2018
  
      You need to tell MATLAB how many 0's are being concatenated in the upper right corner. E.g.,
A = [Aa  zeros(size(Aa,1),size(Af,2));-Af*Ca  Af];
3 Kommentare
  the cyclist
      
      
 am 1 Mai 2018
				
      Bearbeitet: the cyclist
      
      
 am 1 Mai 2018
  
			This code, which is exactly what you posted (with a bit of reformatting), and James' correction, worked for me.
Af=diag([-10 -10]);
Ca=[-0.05540 -0.6511 5.1620 0 112.2000 3.0360 152.9000 1.1390;
    -0.00804 -0.0850 0.2943 0 -2.9510 -0.0590 -26.5500 -0.1560];
Aa=[-0.01320 0 0 9.8100 0 0 0 0;
    -0.08560 -0.9903 -241.7000 0 21.7500 0.9504 18.0800 -0.00073;
    -0.00017 0.0159 -0.9883 0 -0.4850 -0.0323 -3.3200 -0.10450;
    0 0 1 0 0 0 0 0;
    0 0 0 0 0 1 0 0;
    0.08420 0.8897 -3.0300 0 -164.6000 -4.2050 -28.0500 -0.59690;
    0 0 0 0 0 0 0 1;
    -0.02920 -0.1723 -5.0970 0 -2.8540 -0.4456 -430.5000 -2.15500];
A = [Aa  zeros(size(Aa,1),size(Af,2));-Af*Ca  Af];
Note that John changed
-Af.*Ca
to
-Af*Ca
to make it a matrix multiplication. Your code, which would do element-by-element multiplication would fail because you cannot do that between a 2x2 and a 2x8. Whether that type of multiplication is what you need is up to you to determine.
Diese Frage ist geschlossen.
Siehe auch
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!




