Split variable length vector by parts
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So it's probably an easy solution, but can't really find the answer that quick.
I have the following vector:
V = [1 2 3 4 5 ... n];
P = ceil(length(V/127)); %dont know if ceil or floor is better
And then I want to split the vector `V` in parts `P`, so that I'll get something like the following:
% as an example n = 2184 & P = 17
C = {[1 2 3 ... 18],[18 19 20 ... 35],...[2167 2168 2169 ...2184]};
Thanks in advance
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Ameer Hamza
am 25 Apr. 2018
Bearbeitet: Ameer Hamza
am 25 Apr. 2018
You mentioned that P=17 but your first element of C contain 18 elements. What to do, if elements of V can't be divided properly, e.g. 2184/17 is not an integer. How do you want to handle it?
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dpb
am 25 Apr. 2018
L-length(V);
P=17;
id2=[repmat(P,1,fix(L/P)) rem(L,P)]; % number elements in cell size P matching L plus remainder
C=mat2cell(V,1,id2);
That's for the nearest multiple of P with whatever is left over tacked onto the end irregardless of its size relative to P. If it's needed to make as near even as possible need more logic to choose the bin size; that's not a given criterion in the question posed, however.
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