How to find all possible routes with a given node matrix?

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Jung Sunghun
Jung Sunghun am 25 Apr. 2018
Kommentiert: Jung Sunghun am 20 Okt. 2018
Hello,
I am trying to write a function to find all possible routes from the Start node, 6, to the Goal node, 21, with the given node matrix, A, as shown in the below.
A =
1 6
1 23
2 3
2 4
2 5
3 2
4 2
4 7
5 2
5 11
6 1
6 26
7 4
7 8
8 7
8 9
8 24
9 8
9 23
10 11
10 13
10 15
10 16
11 5
11 10
12 13
12 14
13 10
13 12
13 24
14 12
14 19
15 10
15 17
16 10
16 17
16 18
17 15
17 16
17 25
18 16
18 19
18 22
19 14
19 18
19 20
20 19
21 22
21 27
22 18
22 21
22 25
23 1
23 9
24 8
24 13
25 17
25 22
26 6
27 21
I would like to build a function which results the following outputs.
[6,1,23,9,8,7,4,2,5,11,10,15,17,25,22,21]
[6,1,23,9,8,7,4,2,5,11,10,15,17,16,18,22,21]
[6,1,23,9,8,7,4,2,5,11,10,16,17,25,22,21]
[6,1,23,9,8,7,4,2,5,11,10,16,18,22,21]
[6,1,23,9,8,24,13,10,15,17,25,22,21]
[6,1,23,9,8,24,13,10,16,17,25,22,21]
[6,1,23,9,8,24,13,10,16,18,22,21]
[6,1,23,9,8,24,13,12,14,19,18,16,10,15,17,25,22,21]
[6,1,23,9,8,24,13,12,14,19,18,16,17,25,22,21]
[6,1,23,9,8,24,13,12,14,19,18,22,21]
Thank you very much for your invaluable time to help on this problem.
Best regards,
Sunghun Jung
  3 Kommentare
Walter Roberson
Walter Roberson am 15 Okt. 2018
You effectively have an undirected graph. There are an infinite number of routes unless you add constraints.
Jung Sunghun
Jung Sunghun am 15 Okt. 2018
Dear Sir,
The constraint is that the node could only be used once in the path.

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Akzeptierte Antwort

Bruno Luong
Bruno Luong am 15 Okt. 2018
Bearbeitet: Bruno Luong am 15 Okt. 2018
I found actually 13 paths, more than the 10 you have listed:
[6 1 23 9 8 7 4 2 5 11 10 13 12 14 19 18 16 17 25 22 21]
[6 1 23 9 8 7 4 2 5 11 10 13 12 14 19 18 22 21]
[6 1 23 9 8 7 4 2 5 11 10 15 17 16 18 22 21]
[6 1 23 9 8 7 4 2 5 11 10 15 17 25 22 21]
[6 1 23 9 8 7 4 2 5 11 10 16 17 25 22 21]
[6 1 23 9 8 7 4 2 5 11 10 16 18 22 21]
[6 1 23 9 8 24 13 10 15 17 16 18 22 21]
[6 1 23 9 8 24 13 10 15 17 25 22 21]
[6 1 23 9 8 24 13 10 16 17 25 22 21]
[6 1 23 9 8 24 13 10 16 18 22 21]
[6 1 23 9 8 24 13 12 14 19 18 16 10 15 17 25 22 21]
[6 1 23 9 8 24 13 12 14 19 18 16 17 25 22 21]
[6 1 23 9 8 24 13 12 14 19 18 22 21]
Test code:
A =[ 1 6
1 23
2 3
2 4
2 5
3 2
4 2
4 7
5 2
5 11
6 1
6 26
7 4
7 8
8 7
8 9
8 24
9 8
9 23
10 11
10 13
10 15
10 16
11 5
11 10
12 13
12 14
13 10
13 12
13 24
14 12
14 19
15 10
15 17
16 10
16 17
16 18
17 15
17 16
17 25
18 16
18 19
18 22
19 14
19 18
19 20
20 19
21 22
21 27
22 18
22 21
22 25
23 1
23 9
24 8
24 13
25 17
25 22
26 6
27 21];
p = gallpaths(A,6,21);
for k=1:length(p)
fprintf('%s\n', mat2str(p{k}));
end
Using this function GALLPATHS I made
function p = gallpaths(A,start,last)
% find all direct paths from start to last
% A is (n x 2) each row is an edges
A = sortrows(A);
b = true(size(A,1),1);
p = gapengine(A,b,start,last);
end
function p = gapengine(A,b,start,last)
% recursive engine
if start==last
p = {last};
else
bs = A(:,1) == start;
next = A(bs & b,2);
p = {};
b(bs) = false;
for k=1:length(next)
i = next(k);
pk = gapengine(A,b,i,last);
pk = cellfun(@(p) [start, p], pk, 'unif', 0);
p = [p, pk];
end
end
end
  3 Kommentare
Bruno Luong
Bruno Luong am 15 Okt. 2018
Nope find all paths has exponential complexity. AFAIK this is intrinsic to the problem you want to solve rather than the algorithm.
Jung Sunghun
Jung Sunghun am 15 Okt. 2018
I got it. Thank you very much for your invaluable time. Have a great day!

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Weitere Antworten (1)

Walter Roberson
Walter Roberson am 15 Okt. 2018

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