In a matrix how to replace zero by NaN.?

Hi every one, I have a matrix A=1×180. All values of matrix A are either zeros or negative numbers. I need to replace all the zeros by NaN, noted that zeros are also randomly distributed in matrix A. I have tried for loop but do not get the desired result. Any guidance will be appreciated thanks.

[拓郎 下山]

I have the same problem.

I change 0 value to NaN value in nifti file of int16.

I try "V(V==0) = NaN;"

But, it doesn't work. Could you give me the answer?

Thank you for reading.

Answer 1

[njj1]

Try this:

A(A==0) = NaN;

[Safi ullah]

@ njj1, thanks it works well.

[Ambati Sathvik]

Thank you

[laith awwad]

HOW TO NAME THE VARIABLE BECAUSE IF I RIGHT FOR EXAMPLE e = A(A==0) = NaN; GIVES ME AN ERROR

[Steven Lord]

If you want to keep the original array around, make a copy of it then replace the values in that copy.

A = randperm(10)

A = 1×10

9 5 7 3 8 10 2 1 4 6

B = A;
B(B > 7) = NaN

B = 1×10

NaN 5 7 3 NaN NaN 2 1 4 6

[A; B] % Use both the original vector (A) and the modified one (B)

ans = 2×10

9 5 7 3 8 10 2 1 4 6 NaN 5 7 3 NaN NaN 2 1 4 6