Converting the 3D Matrix to 2D Matrix
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Marimuthu Ananthavelu
am 16 Apr. 2018
Kommentiert: Marimuthu Ananthavelu
am 18 Apr. 2018
I have a matrix outputs from my function in the following form;
zeros(3,5,5)
Basically, its a result of pairwise comparison of a matrix
(5 x 5)
for
3
different modalities (types).
I wish to convert this matrix with each pairwise comparison matrix separately with respect to different modalities.i.e I wish to have the result as below;
1 2 3
i1 j1 k1
i2 j2 k2
i3 . .
i4 . .
i5 . .
i6 . .
. . .
. . .
. . .
. . .
i25 j25 k25
I checked the example using Reshape and could not get much from it. Can anyone please help me through? Thanks
2 Kommentare
Jan
am 16 Apr. 2018
I do not understand, what "i1, j1, k1" means. Where are they found in the original data? The problem can be solved by:
y = reshape(permute(reshape(x, Size1), Order2), Size3)
All you need is to find the matching parameters Size1, Order2 and Size3.
Akzeptierte Antwort
Jan
am 16 Apr. 2018
Bearbeitet: Jan
am 16 Apr. 2018
The general reordering of elements can be done by:
y = reshape(permute(reshape(x, Size1), Order2), Size3)
In your case (perhaps - still not sure what "i1, j1, k1 etc" means):
x = zeros(3,5,5); x(:) = 1:3*5*5; % Some test data y = reshape(permute(reshape(x, 3, 25), [2, 1]), [25, 3])
If this is the wanted output, there is an abbreviation:
y = reshape(x, 3, 25).'
permute(Matrix, [2,1]) is the same as mtranspose() and the 2nd reshape is not required here. But it is worth to keep the general transformation in mind.
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