could anyone help me to find the solution for the issue
1 Ansicht (letzte 30 Tage)
Ältere Kommentare anzeigen
Prabha Kumaresan
am 12 Apr. 2018
Kommentiert: KSSV
am 12 Apr. 2018
could anyone help me to solve the issue for the following code: G_part=[5 9 0 0 5; 2 6 0 0 4] G_part=[0 0 4 2 0; 0 0 3 1 0] P_part=[1 3 0 0 2; 4 5 0 0 6] P_part=[0 0 5 7 0; 0 0 6 8 0]
for j=1:size(G_part,2)
for i=1:size(P_part,1)
throughput(i,j) =(C.*log2(1+(P_part(i,j)).*(G_part(i,j))))
end
end
for the above code the throughput was calculated with respect to G_part=[0 0 4 2 0; 0 0 3 1 0] and P_part=[0 0 5 7 0; 0 0 6 8 0]
could anyone tell me how to calculate the throughput with respect to
G_part=[5 9 0 0 5;
2 6 0 0 4] and
P_part=[1 3 0 0 2;
4 5 0 0 6]
1 Kommentar
Akzeptierte Antwort
KSSV
am 12 Apr. 2018
YOu need not to use a loop:
G_part=[5 9 0 0 5;
2 6 0 0 4] ;
P_part=[1 3 0 0 2;
4 5 0 0 6] ;
throughput =(C.*log2(1+(P_part).*(G_part)))
3 Kommentare
KSSV
am 12 Apr. 2018
Read about cell or 3D matrix.
G_part{1}=[5 9 0 0 5;
2 6 0 0 4] ;
P_part{1} =[1 3 0 0 2;
4 5 0 0 6] ;
G_part{2}=[0 0 4 2 0;
0 0 3 1 0] ;
P_part{2}=[0 0 5 7 0;
0 0 6 8 0] ;
G_part{3}=[0 0 1 5 0;
0 0 4 1 0] ;
P_part{3}=[0 0 3 4 0;
0 0 5 6 0] ;
G_part{4}=[1 2 0 0 7;
3 4 0 0 6] ;
P_part{4}=[3 4 0 0 1;
7 8 0 0 2] ;
G_part{5}=[0 0 1 6 0;
0 0 4 5 0] ;
P_part{5}=[0 0 3 4 0;
0 0 5 6 0] ;
C=20;
N = length(G_part) ;
throughput = cell(N,1) ;
for i = 1:N
throughput{i} =(C.*log2(1+(P_part{i}).*(G_part{i}))) ;
end
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Quadratic Programming and Cone Programming finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!