loop over a list of numbers

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alpedhuez am 8 Apr. 2018
I would like to run a loop over a list of numbers like {3,6,18}. Please advise.

Akzeptierte Antwort

Star Strider
Star Strider am 8 Apr. 2018
The loop, if one is appropriate, depends on what you want to do.
This is an example of how to address them:
numlist = {3,6,18};
for k1 = 1:length(numlist)
fprintf('Number at position %d = %6.2f\n', k1, numlist{k1})

Weitere Antworten (3)

Muhammad Asad
Muhammad Asad am 21 Dez. 2018
for i = [3, 6,18]
%do something
  1 Kommentar
Raphaël Nussbaumer
Raphaël Nussbaumer am 29 Sep. 2023
Bearbeitet: Raphaël Nussbaumer am 29 Sep. 2023
Just a note for those of you that make the same mistake. the list needs to be row vector and it doesn't work with column vector such as:
for i = [3, 6,18]'
%do something

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Walter Roberson
Walter Roberson am 8 Apr. 2018
for K=[3, 6,18]
Note: you will find that often you turn out to need a different structure,
kvals = [3,6,18];
numk = length(kvals);
results = zeros(1, numk);
for kidx = 1 : numk
K = kvals(kidx) ;
results(kidx) =....
You would need this kind of structure when you need one output for each of the different values.

Shivani Dixit
Shivani Dixit am 1 Jun. 2021
For looping over each element of an array or list , you can use for loop or while loop according to convenience. Simply using a for loop would answer your question.
len =length(given_array)
for i=1:len
% some operation here or access the array elements using given_array(i)
You can leverage the documentation for loops using


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