how to reshape a matrix using for loop

so i have this matrix called A that is 4772 X 1 in size and i want to reshape it in a "dummy matrix" with dimensions Rows (214) by Columns (223) but in a specific way.

The first value i want to place it is int the bottom-left corner , (last row, first column) and then use a for loops to continue iterate along the columns, in the last row , Once the last column is reached, pivot up one row then this process repeats.

so far i have this but im not doing it correctly.. can anyone help me?!

if true
  % code
end
A= rand(4772,1);
dummy= zeros(214,223);
[m,n]=size(dummy);

if true
  % code
end
count = 1;
for i= n:-1:1
  for j =1:1:m
       dummy(m,n) = A(count);
       count = count + 1;
  end
end
dummy

Answer 1

[James Tursa]

Try switching the m and n in your for-loop indexing, and use (i,j) for your indexed assignment instead of (m,n). E.g.,

for i= m:-1:1
  for j =1:1:n
     dummy(i,j) = A(count);

Btw, there is an easy way to do this without for-loops, but I assume you were instructed to use for-loops for this.

[Tony Garcia]

oh that's right.. thank you.. i did i typo there.. but im not sure with this code still the right answer to my question?