For each fmincon it overwrites the previous values, meaning at the end there is only 1 set of values when there should be 100. The code is running 100 times and displays all sets of values but not storing all sets. How do I resolve this?
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Scott Sanders
am 2 Apr. 2018
Kommentiert: Scott Sanders
am 3 Apr. 2018
for X=1:1:10
for Y=1:1:10
ObjFcn = @myObjective;
x0 = [10 0.001 7];
LB = [0 0 0];
UB = [50 0.5 7.5];
ConsFcn = @(x)myConstraints(x,X,Y);
[x] = fmincon(ObjFcn,x0,[],[],[],[],LB,UB,ConsFcn);
disp(x)
disp(myObjective(x))
end
end
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Alan Weiss
am 2 Apr. 2018
Your code is inefficient in that you define many things inside the loop that should be assigned outside the loop. Using Walter's suggestion, try this:
ObjFcn = @myObjective;
x0 = [10 0.001 7];
LB = [0 0 0];
UB = [50 0.5 7.5];
x = zeros(10,10); % initialization
for X=1:10
for Y=1:10
ConsFcn = @(x)myConstraints(x,X,Y);
x(X,Y) = fmincon(ObjFcn,x0,[],[],[],[],LB,UB,ConsFcn);
disp(x(X,Y))
disp(myObjective(x(X,Y)))
end
end
5 Kommentare
Walter Roberson
am 2 Apr. 2018
ObjFcn = @myObjective;
x0 = [10 0.001 7];
LB = [0 0 0];
UB = [50 0.5 7.5];
x = zeros(10,10,3 ); % initialization
fvals = inf(10,10); % initialization
for X=1:10
for Y=1:10
ConsFcn = @(x)myConstraints(x,X,Y);
[x(X,Y,:), fvals(X,Y)] = fmincon(ObjFcn,x0,[],[],[],[],LB,UB,ConsFcn);
disp(x(X,Y))
disp(myObjective(x(X,Y)))
end
end
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