how to match two consecutive items

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Mekala balaji
Mekala balaji am 29 Mär. 2018
Kommentiert: Mekala balaji am 13 Apr. 2018
Hi,
I have below data:
Start
PAJ04
Type
Model
End
time
2018-01-2
Data aquire
Start
time
-
Date
2018-02-10
Start time
00:12:24
End
time
00:32:15
Acquired
time
01:15:26
Running sequence
AT09K00
I want catch Date, Start time, End time, acquired time, and running sequence
but some time end time occurs multiple time. I want to catch the first occurrence after the start time
Desired output
Date Start time End time Acquired time Running sequence
2018-02-10 00:12:24 00:32:15 01:15:26 AT09K00
alos How to string match two cosequtive rows for example: to catch "start time:
match first line is "Start", immediate row to be matched is "time", then it is Start time

Antworten (1)

Elias Gule
Elias Gule am 29 Mär. 2018
Assuming that you have stored your text in a variable named "txt". The following code should do what you want.
txt = regexprep(txt,'\r?\n',' '); %%replace carriage return and newline character with whitespace
pattern = {'(Date\s*\d{4}-\d{2}-\d{2})',...
'(Start\s*time\s*(\d{2}:\d{2}:\d{2}))',...
'(End\s*time\s*(\d{2}:\d{2}:\d{2}))',...
'(Acquired\s*time\s*(\d{2}:\d{2}:\d{2}))',...
'(Running\s*sequence\s*\w+)'};
output = regexpi(txt,pattern,'match');
output = cellfun(@(x) regexp(x,'\s(?=\d)|(?<=sequence)\s+','split'),...
output,'uni',0);
headerline = char(join(cellfun(@(x) sprintf('%-20s',x{1}{1}),output,'uni',0)));
values = char(join(cellfun(@(x) sprintf('%-20s',x{1}{2}),output,'uni',0)));
output_txt = sprintf('%s\n%s',strtrim(headerline),strtrim(values))
  1 Kommentar
Mekala balaji
Mekala balaji am 13 Apr. 2018
Error using regexpi Multiple strings and patterns given must have the same quantity.

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