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How to find out particular value of t (j) at which y(j) is equal to some value lets say 4 (without looking graph) ? Thanks.

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N=100;
dt=0.05;
k=2;
t=zeros(N,1);
y=zeros(N,1);
y(1)=2;t(1)=0;
for j=1:N-1
t(j+1)=t(j)+dt;
y(j+1)=y(j)+dt*(2+k);
end
plot(t,y)

Antworten (1)

Star Strider
Star Strider am 27 Mär. 2018
Try this:
yi = 4
ti = interp1(y, t, yi)

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